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Triangle $ABC$ has its vertices $A$, $B$, and $C$ on the sides of a rectangle 4 units by 5 units as shown. What is the area of triangle $ABC$ in square units?

User Nate Thorn
by
7.9k points

2 Answers

6 votes

Answer:

9

Explanation:

User Vencovsky
by
8.0k points
4 votes

Answer:

10 square units.

Explanation:

It is given that triangle ABC has its vertices A, B, and C on the sides of a rectangle 4 units by 5 units.

Height of triangle = 4 units

Base of triangle = 5 units

We need to find the area of triangle.

Area of triangle
=(1)/(2)* base * height

Substitute base = 5 and height = 4 in the above formula.

Area of triangle
=(1)/(2)* 5* 4

Area of triangle
=(20)/(2)

Area of triangle
=10

Therefore, the area of triangle ABC is 10 square units.

User Retrovius
by
7.9k points
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