Question

The product of 2 non zero numbers is equal to twice the sum. Find the sum of their reciprocals

Answer 1

1/2

Explanation:

Answer 2

1/2

Explanation:

Let the two numbers be
`a` and
`b.`

We already know that
`a\\eq 0` and
`b\\eq 0`.

Write an equation:

`ab=2(a+b)`

The product (ab) is equal to twice the sum (2(a+b)).

Now, write an equation for the sum of their reciprocals:

`S=(1)/(a)+(1)/(b) =(a+b)/(ab)`.

Rewrite the denominator:

`=(a+b)/(2(a+b)) =1/2`

`S=(1)/(a)+(1)/(b)=1/2`