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Which function in vertex form is equivalent to f(x) = x2 + 8 – 16x? f(x) = (x – 8)2 – 56 f(x) = (x – 4)2 + 0 f(x) = (x + 8)2 – 72 f(x) = (x + 4)2 – 32

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Answer:

f(x) = x² + 8 - 16x

= x² - 16x + 8

= (x² - 16x + 64) - 64 + 8

= (x - 8)² - 56

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