Answer:
The path way A-B-D involves a catalyst and is slower than A-C-D
Step-by-step explanation:
The diagram above shows the path taken by a chemical reaction when a catalyst is used and also when no catalyst is used.
The catalyzed path is indicated with the broken lines i.e the path A-B-C while the uncatalyzed path is indicated with the small thick line i.e the path A-C-D.
The catalyzed path has a higher peak (activation complex) than the uncatalyzed path. This implies that the activation energy of the catalyzed path is higher than that of the uncatalyzed path. Therefore more energy will be required to overcome the barrier (i.e the activation energy) in the catalyzed path and hence the reaction will be slower when compared to the uncatalyzed path which have a lower energy barrier (i.e the activation energy) and needs little energy to overcome the energy barrier (i.e the activation energy).
Note: reaction with high activation energy tends to be slower when compared with those with low activation energy.