Answer:
Bob's home will worth $296,779.25 after 12 years.
Equation used is
![FV = $175,000( 1 + 4.5/100)^(12)\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/etaxae0l8xmssqlkcbsjdzobnihj4oqnsp.png)
Explanation:
Current value of Bob's house =
![FV = $175,000( 1 + 4.5/100)^12\\FV = $175,000( (100+ 4.5)/100)^12\\FV = $175,000( (104.5)/100)^12\\FV = $296,779.25](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pvi3o7jys3n32nfdc97c2ikh5u7dyd2ip4.png)
market is improving at 4.5% annually.
This, means that the value of house gets appreciated by 4.5% each year from its previous year value.
This is a problem of compound interest formula
![FV = PV(1+r/100)^n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ok6s8xqqcmtltxekdlq2vx8fwgn0g88rpa.png)
where PV is the present value of any thing
FV is the future value
r is the annual rate of interest
t is the time in number of year for which rate is applicable.
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Given
PV = $175,000.
r = 4.5%
t = 12 years
Value after 12 year will be given by
![FV = $175,000( 1 + 4.5/100)^(12)\\FV = $175,000( (100+ 4.5)/100)^(12)\\FV = $175,000( (104.5)/100)^(12)\\FV = $296,779.25](https://img.qammunity.org/2021/formulas/mathematics/middle-school/je5m8tyxt8cdsame1dqr5lyjqau3hojnxf.png)
Thus, Bob's home will worth $296,779.25 after 12 years.
Equation used is
![FV = $175,000( 1 + 4.5/100)^(12)\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/etaxae0l8xmssqlkcbsjdzobnihj4oqnsp.png)