Answer:
C. 2(x-4)^2
Explanation:
To factorize 2x^2-16x+32
We have to take it step by step and know if it's factorizable then if it is we will look for the answer.
2x^2-16x+32 = 2x² -16x +(2x²)(32)
2x^2-16x+32= 2x² -16x +64x²
I'll ask myself what do i multiply to give me +64x² and add to get -16x.
It's simple.
The answer is -8x
-8x *-8x = 64x²
-8x+-8x = -16x
2x^2-16x+32= 2x² -16x +32
2x^2-16x+32=2x²-8x-8x+32
2x^2-16x+32= 2x(x-4)-8(x-4)
2x^2-16x+32=(2x-8)(x-4)
2x^2-16x+32=2(x-4)(x-4)
2x^2-16x+32=2(x-4)²