Question

A projectile is fired with an initial speed of 150 m/s and angle of elevation 60°. (Recall g ≈ 9.8 m/s2. Round your answers to the nearest whole number.) (a) Find the range of the projectile.

Answer 1

1988 m

Step-by-step explanation:

Range of a projectile

R = U²sin2∅/g...................... Equation 1

Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.

Given: U = 150 m/s, ∅ = 60°

Constant: g = 9.8 m/s².

Substitute these values into equation 1

R = 150²(sin60°)/9.8

R = 22500(0.866)/9.8

R = 1988 m

Hence the Range of the projectile is 1988 m