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Type the correct answer in each box. If necessary, use/for the fraction bar(s).

In this triangle, the product of Sin B and tan C is_____, and the product of sin C and tan B is_____.

please view picture at the top

Type the correct answer in each box. If necessary, use/for the fraction bar(s). In-example-1
User Wun
by
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1 Answer

7 votes

Answer:

1). sinB × tanC =
(c)/(a)

2). sinC × tanB =
(b)/(a)

Explanation:

From the figure attached,

A right triangle has been given with m∠A = 90°, m(AC) = b, m(AB) = c and m(BC) = a

SinB =
\frac{\text{Opposite side}}{\text{Hypotenuse}}

=
\frac{\text{AC}}{\text{BC}}

=
(b)/(a)

tanB =
\frac{\text{Opposite side}}{\text{Adjacent side}}

=
\frac{\text{AC}}{\text{AB}}

=
(b)/(c)

SinC =
\frac{\text{Opposite side}}{\text{Hypotenuse}}

=
\frac{\text{AB}}{\text{BC}}

=
(c)/(a)

tanC =
\frac{\text{Opposite side}}{\text{Adjacent side}}

=
(c)/(b)

Now sinB × tanC =
(b)/(a)* (c)/(b)

=
(c)/(a)

And sinC × tanB =
(c)/(a)* (b)/(c)

=
(b)/(a)

User Rych
by
7.8k points

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