Answer:
y-9 = -1/12(x-8)
Explanation:
To write an equation of a line perpendicular to the graph of y = 12x-3 and passing through the point, we will follow the following steps.
The standard form of point-slope form of the equation of a line is given as
y − y1 = m(x − x1),
m is the slope of the unknown line
(x1, y1) is a point on the line.
Step 1: We need to calculate the slope of the known line first,
Given y = 12x-3
from the equation, m = 12 on comparison.
Step 2: get the slope of the unknown line. since the line given is perpendicular to the line y = 12x - 3, the product of their slope will be -1 i.e Mm = -1
M = -1/m
M is the slope of the unknown line
M = -1/12
Step 3: We will substitute M = -1/12 and the point (8, 9) into the point-slope form of the equation of a line i.e y − y1 = M(x − x1),
M = -1/12, x1 = 8 and y1 = 9
y-9 = -1/12(x-8)