Question

If 75 kJ of heat is transferred to 1200 g liquid water at 36°C, what would the

new temperature of the water be? (The specific heat capacity of liquid water
is 4.186 J/g.°C.)​

Answer 1

50.9° (corrected to 3 significant figures)

Step-by-step explanation:

Energy(J) = mass(kg) x specific heat capacity x temperature change

(E = mcΔT)

Let the new temperature be T.

75000 = (1.2 )(4186)(T-36)

14.930 = T -36

T = 50.9°