Question

Determine the enthalpy change when 19.399999999999999 g of carbon is reacted with oxygen according to the reaction

Answer 1

The enthalpy change is −636.9798 kJ

Step-by-step explanation:

The equation of the reaction between Carbon and Oxygen can be represented as :

`C_((s)) + O_(2(g)) \to CO_(2_(g)) \ \ \ \ \ \ \Delta H = -394 \ \ kJ/mol`

molar mass of Carbon = 12 mole

when mass of 19.399999999999999 g of carbon reacted with oxygen;

the number of moles = mass/molar mass

the number of moles = 19.399999999999999/12

the number of moles = 1.6167 mol

Thus the enthalpy change when 1 mole of carbon react with oxygen = -394 kJ/mol

Therefore when 1.6167 moles react with oxygen; we have:

= 1.6167 mol × -394 kJ/mol

= −636.9798 kJ