Question

A very large sheet of a conductor carries a uniform charge density of on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor?

Answer 1

Complete Question

A very large sheet of a conductor carries a uniform charge density of
`4.00\ pC/mm^2` on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor?

Answer:

The electric field is
`E = 4.5198 *10^(5) \ N/C`

Step-by-step explanation:

From the question we are told that

The charge density is
`\sigma = 4.00pC /mm^2 = 4.00 * 10^(-12 ) * 10^(6) = 4.00 *10^(-6)C/m`

The position outside the surface is
`a = 3.00 \ mm = 0.003 \ m`

Generally the electric field is mathematically represented as

`E = (\sigma)/(\epsilon _o )`

Where
`\epsilon_o` is the permitivity of free space with values
`\epsilon _o = 8.85 *10^(-12) F/m`

substituting values

`E = (4.0*10^(-6))/(8.85 *10^(-12) )`

`E = 4.5198 *10^(5) \ N/C`