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Quadrupling the power output from a speaker emitting a single frequency will result in what increase in loudness (in units of dB)

User Akm
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2 votes

Answer:

6.02 dB increase

Step-by-step explanation:

Let us take the initial power from the speaker P' = P Watt

then, the final power P = 4P Watt

for a given unit area, initial intensity (power per unit area) will be

I' = P Watt/m^2

and the final quadrupled sound will produce a sound intensity of

I = 4P Watt/m^2

Increase in loudness is gotten from the relation

ΔL =
10log_(10) (I)/(I')

where

I = final sound intensity

I' = initial sound intensity

imputing values of the intensity into the equation, we have

==>
10log_(10) (4P)/(P) =
10log_(10) 4 = 6.02 dB increase

User Milan Jaric
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