Question

X+3y+2z=1
2x-2y-5z=0
-x+2y+4z=1

Answer 1

(x, y, z) = (3, -2, 2)

Explanation:

The augmented matrix for this set of equations is ...

`\left[\begin{array}ccc1&3&2&1\\2&-2&-5&0\\-1&2&4&1\end{array}\right]`

Using your calculator or any of a number of web sites, you can find the reduced row-echelon form to be ...

`\left[\begin{array}c1&0&0&3\\0&1&0&-2\\0&0&1&2\end{array}\right]`

This tells you the solution is (x, y, z) = (3, -2, 2).