Answer:
A = 166.66
Explanation:
You have the following functions:

In order to calculate the area of the given region, you first calculate the points at which the function y = x^2-24 intersects the line y=1:

Next, you take into account that the area between the two function is given by:
Where you have used the fact that y2 is above the y1 function.
Next, you calculate the following integral:

Then, the area of the bounded region is 166.66