Answer:
Area of Segment = 3.26 in² (Approx)
Explanation:
Given:
Radius (r) = 6 in
Angle (θ) = 60°
Find:
Area of segment
Computation:
Area of Segment = (θ/360)πr² − (1/2)r²sin(θ)
Area of Segment = (60/360)(22/7)(6)² − (1/2)(6)²sin(60)
Area of Segment = (1/6)(22/7)(36) - (0.5)(36)sin(60)
Area of Segment = 18.8571429 - 15.5884573
Area of Segment = 3.2686856
Area of Segment = 3.26 in² (Approx)