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John cut a paper square with a perimeter of 18 inches into two rectangles. The perimeter of one of the rectangles is 10 inches. What is the perimeter of the second rectangle?

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Answer:

13.5 inches

Explanation:

Perimeter of the paper square = 18inches

Perimeter of a square = 4s

4s = 18 inches

s = 18/4 = 4.5 inches

Therefore, each side of the square = 4.5 inches.

When the square is cut into 2 rectangles,

The perimeter of one of the rectangles is 10 inches.

Perimeter of the second rectangle = 2L + 2W

Let the length of the rectangle (L) = one side of the square = 4.5 inches

Width of the Rectangle = Length of the square/2 = 4.5 inches/ 2 = 2.25

Perimeter of the second rectangle = 2(4.5) + 2(2.25)

= 9 + 4.5

= 13.5 inches

User Selkathguy
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