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Find the area of a triangle whose two sides are 12 inches and 14 inches long, and has a perimeter of 34 inches.

1 Answer

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Answer:


\huge\boxed{A=3√(255)\ in^2\approx47.91\ in^2}

Explanation:

We have two sides


a=12in;\ b=14in

and the preimeter


P=34in

We can calculate the length of the third side:


c=P-a-b

substitute


c=34-12-14=8\ (in)

Use the Heron's formula:


A=\sqrt{p(p-a)(p-b)(p-c)

where


p=(P)/(2)

substitute:


p=(34)/(2)=17\ (in)\\\\A=√(17(17-12)(17-14)(17-8))=√((17)(5)(3)(9))\\\\=√(9)\cdot√((17)(5)(3))=3√(255)\ (in^2)\approx47.91\ (in^2)

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