Answer:
0.82 m
Step-by-step explanation:
Given:
v₀ᵧ = 4 m/s
aᵧ = -9.8 m/s²
Find: Δy when vᵧ = 0 m/s
vᵧ² = v₀ᵧ² + 2aᵧΔy
(0 m/s)² = (4 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 0.82 m
The maximum height reached by the athlete is 0.82 meters. The jump is not successful.