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If 1.00 mol of nitrogen monoxide gas and 1.00 mol of oxy-gen gas react, what is the limiting reactant and how many moles of NO2 are produced from the reaction

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Answer:

Limiting Reactant = NO

Number of moles of NO2 formed = 1

Step-by-step explanation:

First thing's first, we have to write out the balanced chemical equatin. This is given as;

NO + O2 --> NO2

Upon balancing we have;

2NO + O2 --> 2NO2

From the stoichiometry of the reaction, we can tell that 2 moles of NO reacts with 1 mole of O2 to form 2 moles of NO2.

If we have 1 mol of Nitrogen monoxide and 1 mol of oxygen, the limiting reactant is NO.

This is because 1 mol of No would require 0.5 mol of O2. So we have an excess of Oxygen while the NO has been used up.

Limiting reactant = NO

since the mole ratio between NO and NO2 is 2:2 it means that 1 mol of NO would also form 1 mol of NO2.

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