Question

There are 10 sweets in a bag.

4 are red, 2 are green, 3 are yellow and 1 is purple.

OOOOOOOOOO

A sweet is chosen at random from the bag.

Here is a probability scale:

B C

a) Which letter shows the probability of choosing a yellow sweet?

b) Which letter shows the probability of choosing a sweet that is not orange?

Wenn

Answer 1

/

Explanation:

Answer 2

See Explanation Below

Explanation:

Given

Total Sweets = 10

Red = 4

Green = 2

Yellow = 3

Purple = 1

Required

a & b

The question is not properly presented; however the solution is as follows;

A.

Let P(Yellow) represent the probability of selecting a yellow sweet and n(Yellow) represent the number of Yellow sweets;

`P(Yellow) = (n(Yellow))/(Total)`

`P(Yellow) = (4)/(10)`

`P(Yellow) = 0.4`

So, whichever letter that shows
`0.4` or
`(4)/(10)` is the probability of choosing a yellow sweet

B.

Let P(Orange) represent the probability of selecting an orange sweet and n(Orange) represent the number of orange sweets;

Since, there's no orange sweet in the bag;

`n(Orange) = 0`

`P(Orange) = (n(Orange))/(Total)`

`P(Orange) = (0)/(10)`

`P(Orange) = 0`

In probability; opposite probabilities add up to 1;

Let P(Not\ Orange) represent the probability of choosing a sweet that is not orange

`P(Not\ Orange) + P(Orange) = 1`

Substitute
`P(Orange) = 0`

`P(Not\ Orange) + 0 = 1`

`P(Not\ Orange) = 1`

So, whichever letter that shows 0 is the probability of choosing a sweet that is not orange