Question

A pendulum that has a period of 2.67000 s and that is located where the acceleration due to gravity is 9.77 m/s2 is moved to a location where it the acceleration due to gravity is 9.81 m/s2. What is its new period? (Enter your answer in seconds and to at least 5 decimal places.)

Answer 1

Step-by-step explanation:

Expression for time period of pendulum is given as follows

`T=2\pi\sqrt{(l)/(g) }`

where l is length of pendulum and g is acceleration due to gravity .

Putting the given values for first place

`2.67=2\pi\sqrt{(l)/(9.77) }`

Putting the values for second place

`T=2\pi\sqrt{(l)/(9.81) }`

Dividing these two equation

`(T)/(2.67) =\sqrt{(9.77)/(9.81) }`

T = 2.66455 s.