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Help me round to the nearest tenth 5x^2-27=6x

Help me round to the nearest tenth 5x^2-27=6x-example-1
User Rick M
by
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1 Answer

5 votes

Answer:

-1.8,3

Explanation:

This type of problem often results in two answers for X, and to get it, I often like to rearrange the formula to look like this: 5x^2-6x-27. There are various ways to answer this question, but since this is a quadratic equation, I commend using the quadratic formula! It may look scary, but it is actually really simple. I will attach a picture of this formula for reference when you need it.

looking at our modified formula, a= 5, b=-6, and c= -27. With these values in mind, you can go ahead and plug them in the formula. So it will look like (6±√(-6)²-4(5)(-27) )÷2(5).

Let’s break this down a bit, what this formula is saying is that you’ll have 2 operations to do now, the first one will look like this:


(6+√(576))/10, this will result in 3, which is one of your values for x

the second operation will be exactly the same, but instead of adding 6 to the square root of 576 (pssst, it is 24 btw), you will be subtracting. This second operation once done will result in -1.8, which is rounded to the nearest tenth!

User Lupyana Mbembati
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