Question

What is the increase in the internal energy of the system, if it absorbs 500 cal and at the same time does 85J work on its surroundings? (1 cal = 4.18J)

Answer 1

2005 J

Step-by-step explanation:

500 cal × (4.18 J/cal) = 2090 J

ΔU = q + w

ΔU = 2090 J − 85 J

ΔU = 2005 J