Question

When an old LP turntable was revolving at 3313 rpm, it was shut off and uniformly slowed down and stopped in 5.5 seconds. What was the magnitude of its angular acceleration (in rad/s2) as it slowed down?

Answer 1

-0.63 rad/s²

Step-by-step explanation:

Given that

Initial angular velocity of the turntable, w(i) = 33 1/3 rpm

Final angular velocity of the turntable, w(f) = 0 rpm

Time taken to slow down, t = 5.5 s

The calculation is attached in the photo below