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A ball, thrown vertically upwards, from the ground, has its height h (in meters) expressed as a function of time t (in seconds), elapsed after the launch, by the law h(t) = 20t - 5t2. According to this information, determine the height at which the ball is 3 seconds after the throw and the maximum height reached by the ball.

2 Answers

5 votes
15 meters and 20 meters
User Osman Cea
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2 votes

Answer:

pen

Explanation:

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User Matthew Jacobs
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