Question

Which equation has the solutions x = 1 plus-or-minus StartRoot 5 EndRoot? x2 + 2x + 4 = 0 x2 – 2x + 4 = 0 x2 + 2x – 4 = 0 x2 – 2x – 4 = 0

Answer 1

Answer: D!!!!!!!

Explanation:

Answer 2

x^2 - 2x - 4 = 0.

Explanation:

Written in factor form we have:

(x - ( 1 + √5)( x - (1 - √5)) = 0

(x - 1 -√5)( x - 1 +√5)) = 0 Expanding:

x^2 - x +√5x - x + 1 - √5 - √5x + √5 - 5 = 0

x^2 - 2x - 4 = 0.