90.1k views
0 votes
(4x-5)^3 - (x^2 + 4x+1)(4x-3)=?

User AlexCon
by
7.9k points

2 Answers

0 votes

Answer:

60x^3-253x^2+308x-122

Explanation:

(4x-5)^3-(x^2+4x+1)(4x-3)

=64x^3-240x^2+300x-125-(x^2+4x+1)(4x-3)

=(4x)^3-3(4x)^2*5+3*4x*5^2-5^3

=64x^3-240x^2+300x-125

=-(4x^3+13x^2-8x-3)

=-(4x^3)-(13x^2)-(-8x)-(-3)

=-4x^3-13x^2+8x+3

=64x^3-240x^2+300x-125-4x^3-13x^2+8x+3

=64x^3-4x^3-240x^2-13x^2+300x+8x-125+3

=64x^3-4x^3-253x^2+300x+8x-125+3

=60x^3-253x^2+300x+8x-125+3

=60x^3-253x^2+308x-125+3

=60x^3-253x^2+308x-122

So the Answer is 60x^3-253x^2+308x-122.

God Bless, Hope it helps!!!!!!!

User Andrew Hampton
by
9.7k points
1 vote

Answer:

64x^3-241x^2+296x-125

Explanation:

User CgodLEY
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories