Question

Calculate the magnitude of the magnetic field at a point 16.0 cm from a long, thin conductor carrying a current of 3.50 A.

Answer 1

The magnitude of the magnetic field is
`B = 1.392 *10^(-6) \ T`

Step-by-step explanation:

From the question we are told that

The distance of the position that is being considered to the conductor is

`d = 16 \ cm = 0.16 \ m`

The current flowing through conductor is
`I = 3.50 \ A`

Generally the magnitude of the magnetic field due to a current carrying conductor is mathematically represented as

`B = (\mu_o I)/(2 \pi d)`

Where is the permeability of free space with value
`\mu_o = 4\pi * 10^(-7) N/A^2`

substituting values

`B = ( 4\p *10^(-7) *3.50)/(2 * 3.142* 0.16)`

`B = 1.392 *10^(-6) \ T`