Question

Please help I do not understand

calculate the coefficients of the first four terms of the binomial expansion for the binomial (x+y)^28​

Answer 1

The coefficients are;

1,28,378 and 3,276

Explanation:

For the binomial expansion, when we talk of the coefficients, we mean the whole numbers that stands before the alphabets

For example, the coefficient of x in 2x is 2

Back to the question;

(x + y)^28

= 28C0 x^28y^0 + 28C1 X^27y^1 + 28C2 x^26y^2 + 28C3 x^25y^3 + ..........

So the coefficients we are looking for are;

28C0 = 1

28C1 = 28

28C2 = 378

28C3 = 3,276

Kindly note that 28C0 is read as 28 combination zero and so on