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A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to the potential difference between the plates as they are being separated?
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A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to the potential difference between the plates as they are being separated?

User ScootyPuff
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4.6k points

1 Answer

3 votes

Answer:

The potential difference increases

Step-by-step explanation:

from the relation
E= (V)/(d)

where E= electric field (force per coulomb)

V= voltage

d= distance

Hence the voltage is going to be V= E×d.

Therefore this means that increasing the distance increases the voltage.

User RadekJ
by
4.8k points
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