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The time constant of a simple RL circuit is defined as _______. We say that R is the resistance of the circuit and L is the inductance of the circuit.

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Answer:

The correct answer will be "
\tau =(L)/(R)".

Step-by-step explanation:

The time it would take again for current or electricity flows throughout the circuit including its LR modules can be connected its full steady-state condition is equal to approximately 5
\tau as well as five-time constants.

It would be calculated in seconds by:


\tau=(L)/(R)

, where

  • R seems to be the resistor function in ohms.
  • L seems to be the inductor function in Henries.
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