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What is the value of Fraction 1 over 2x3 + 3.4y when x = 2 and y = 5?

18
20
21
37

1 Answer

0 votes

Answer:


C. \
(1)/(2)x^3 + 3.4y = 21

Explanation:

Given


x = 2


y = 5

Required


(1)/(2)x^3 + 3.4y

Substitute 2 for x and 5 for y;

The expression becomes


=\ (1)/(2) * 2^3 + 3.4 * 5

Multiply 3.4 by 5


=\ (1)/(2) * 2^3 + 17

---------------------------


2^3 = 2 * 2 * 2 = 8

--------------------------


=\ (1)/(2) * 8 + 17


=\ (8)/(2) + 17


=\ 4 + 17


=\ 21

Hence;


(1)/(2)x^3 + 3.4y = 21

User Dwight Reynoldson
by
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