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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete the statements below, simplify all ratios and keep them as improper fractions. If cos(θ) = and sin(θ) is negative, then sin(θ) = and tan(θ) = .

User Tracer
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Question:

If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.

Answer:


Sin\theta = (-15)/(17)


Tan\theta = (15)/(8)

Explanation:

Given

cos(θ) =-8/17

Required

sin(θ) = __

tan(θ) =__

The first step is to determine the length of the third side

Given that


cos(\theta) = (Adj)/(Hyp)

Where Adj and Hyp represent Adjacent and Hypotenuse


cos(\theta) = (-8)/(17)

By comparison


Adj = -8\ and\ Hyp = 17

Using Pythagoras


Hyp^2 = Adj^2 + Opp^2

By Substitution


17^2 = (-8)^2 + Opp^2


289 = 64 + Opp^2

Subtract 64 from both sides


289 - 64 = 64 - 64 + Opp^2


225 = Opp^2

Take square roots of both sides


√(225) = √(Opp^2)


√(225) = Opp


15 = Opp


Opp = 15

The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such


Opp = -15

From trigonometry


Sin\theta = (Opp)/(Hyp)


Sin\theta = (-15)/(17)

Also from trigonometry


Tan\theta = Sin\theta / Cos\theta


Tan\theta = (-15)/(17) / (-8)/(17)


Tan\theta = (-15)/(17) * (-17)/(8)


Tan\theta = (-15 * -17)/(17 * 8)


Tan\theta = (15 * 17)/(17 * 8)


Tan\theta = (15)/(8)

User Rafael Fontes
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