Answer:
0.5
Explanation:
Let D be the event of selecting a marble with dots.
Let P be the event of selecting a purple marble.
The probability of selecting a marble with dots, P(D)=0.2
The probability of selecting a marble that is both purple and has dots,
![P(D \cap P)=0.1](https://img.qammunity.org/2021/formulas/mathematics/high-school/wkff3vliypn2rvdcy2oyhzhbq6v2d82h71.png)
We want to determine the probability of selecting a purple marble given that the marble has dots on it, P(P|D)
By the definition of conditional probability:
![P(P|D)= (P(P \cap D))/(P(D)) \\= (0.1)/(0.2)\\ =0.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/i2v3m1r2jjvc1zjmv3ynr97xq93jm6pulu.png)
The probability of selecting a purple marble given that the marble has dots on it is 0.5.