Answer:
5.13g of H2O.
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
HBr(aq) + NaOH(aq) —> NaBr(aq) + H2O(l)
Next, we shall determine the masses of HBr and NaOH that reacted and the mass of H2O produced from the balanced equation.
This is illustrated below:
Molar mass of HBr = 1 + 80 = = 81g/mol
Mass of HBr from the balanced equation = 1 x 81 = 81g
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH from the balanced equation = 1 x 40 = 40g
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H2O from the balanced equation = 1 x 18 = 18g
Thus, from the balanced equation above,
81g of HBr reacted with 40g of NaOH to produce 18g of H2O.
Next, we shall determine the limiting reactant. This is illustrated below:
From the balanced equation above,
81g of HBr reacted with 40g of NaOH.
Therefore, 34g of HBr will react with = (34 x 40)/81 = 16.79g of NaOH.
From the calculations made above, we can see that it will take a higher mass (i.e 16.79g) of NaOH than what was given (i.e 11.4g) to react completely with 34g of HBr.
Therefore, NaOH is the limiting reactant and HBr is the excess react.
Finally, we can determine the maximum mass of H2O produced as shown below.
In this case the limiting reactant will used because it will produce the maximum mass of H2O since all of it is consumed in the reaction.
The limiting reactant is NaOH and the maximum mass of H2O produced can be obtained as follow:
From the balanced equation above,
40g of NaOH reacted to produce 18g of H2O.
Therefore, 11.4g of NaOH will react to produce = (11.4 x 18)/40 = 5.13g of H2O.
Therefore, the maximum mass of H2O produced from the reaction is 5.13g.