Question

A train slowed down from 50km/h to 10km/h in 2 minutes. How far did it travel in this time​

Answer 1

s=0.9 km i believe is the answer

Answer 2

S = 0.9 km

Explanation:

Given:

Initial Velocity =
`V_(i)` = 50 km/hr = 13.89 m/s

Final Velocity =
`V_(f)` = 10 km/hr = 2.78 m/s

Time = t = 2 mins = 120 secs

Required:

Distance = S = ?

Solution:

Using 1st equation of motion:

=>
`V_(f) = V_(i) + at`

=> 2.78 = 13.89 + (a)(120)

=> 120a = 2.78 - 13.89

=> 120a = -11.11

Dividing both sides by 120

=> a = -0.1 m/s²

Now, Finding S by 2nd equation of motion:

S =
`V_(i)t+(1)/(2) at^2`

S = (13.89)(120)+1/2(-0.1)(120)^2

S = 1666.8 - 720

S = 946.8 metres

In kilometers

S = 0.9 km