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What is the difference of rational expressions below 6x/x-3 - 5/x

1 Answer

4 votes

Answer:


$ (6x^2-5x+15 )/(x^2-3x) $

Explanation:


$(6x)/(x-3) -(5)/(x) $


$(6x(x))/(x(x-3)) -(5(x-3))/(x(x-3)) $


$(6x^2)/(x^2-3x) -(5x-15)/(x^2-3x) $


$ (6x^2-5x+15 )/(x^2-3x) $

User Siamak Motlagh
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