Question

Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smaller number. Let x represent the smaller number and y represent the larger number. Which equations represent this situation? y = negative four-thirds x + 31. y = 2 x + 7. y = negative four-thirds x + StartFraction 31 Over 3 EndFraction. Y = 2 x + 7. y = negative four-thirds x + 31. y = negative 2 x + 7. y = negative four-thirds x + StartFraction 31 Over 3 EndFraction. Y = negative 2 x + 7.

Answer 1

first one (A)

Explanation:

Answer 2

Let x represent the smaller number and y represent the larger number

For the first equation

Four times a number added to 3 times a larger number is 31 is written as

4x + 3y = 31

Making y the subject we have

3y = - 4x + 31

Divide both sides by 3

That's

`y = - (4)/(3) x + (31)/(3)`

For the second equation

Seven subtracted from the larger number is equal to twice the smaller number is written as

y - 7 = 2x

Making y the subject

We have

y = 2x + 7

Hope this helps you