Question

Nine balls, each marked with a number from 1 to 9, are placed in a bag and one

Ball is taken out at random. What is the probability that the number on the ball is:

(a) odd, (b) a multiple of 3, (c) 5, (d) not a 7​

Answer 1

a =5/9 b=1/3 c=1/9 d=8/9

Explanation:

there are total 9 numbers

in a

there are 5 odd numbers

in b

there are 3 multiplier of 3

in c

there is only one 5

in d

there are 8 numbers except 7

Answer 2

a) 5/9 b) 1/3 c) 1/9 d) 8/9

Explanation:

a) odd numbers between 1 to 9 are 1,3,5,7,9. so there are 5 odd numbers.

total balls are 9

=> probability is 5/9

b) multiples of 3 = 3, 6,9 there are 3 numbers.

=> probability is = 3/9 = 1/3

c) 5. only one 5 is there between 1 to 9 numbers.

=> probability is 1/9

d) not a 7.

removing 7. there will 8 numbers.

=> probability is 8/9