Question

What must be added to
15x²-10x to make it
perfect square
a​

Answer 1

Explanation:

hello,

`15x^2-10x=15(x^2-(10)/(15)x)=15(x^2-(2)/(3)x)`

and we can write that

`(x-(2)/(2*3))^2=(x-(1)/(3))^2=x^2-(2)/(3)x+(1)/(9)`

so

`x^2-(2)/(3)x= (x-(1)/(3))^2-(1)/(9) \ so\\15x^2-10x=15(x^2-(2)/(3)x)=15[(x-(1)/(3))^2-(1)/(9) ]=15(x-(1)/(3))^2-(15)/(9)\\=15(x-(1)/(3))^2-(5)/(3)`

Then

`15x^2-10x+(5)/(3)=15(x-(1)/(3))^2`

then, I would say that you need to add 5/3 to make a perfect square

hope this helps