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The perimeter of a triangle is 82 feet. One side of the triangle is 2 times the second side. The third side is 2 feet longer than the second side. Find the length of each side.

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Answer:

first side=40

second side=20

third side=22

Explanation:

LET THE SIDES OF THE TRIANGLES BE y

Perimeter=82

first side=2 x y = 2y

second side=y

third side=2 +y

2y + y + 2 + y=82

4y+2=82

4y= 82-2

4y=80

y=80/4

y=20

first side=2y=2(20)=40

second side=y=20

third side= 2 + y= 2 + 20 = 22

User Kiran Paul
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