Answer:
first side=40
second side=20
third side=22
Explanation:
LET THE SIDES OF THE TRIANGLES BE y
Perimeter=82
first side=2 x y = 2y
second side=y
third side=2 +y
2y + y + 2 + y=82
4y+2=82
4y= 82-2
4y=80
y=80/4
y=20
first side=2y=2(20)=40
second side=y=20
third side= 2 + y= 2 + 20 = 22