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the ellipse is centered at the origin, has axes of lengths 8 and 4, its major axis is horizontal. how do you write an equation for this ellipse?​

User Twila
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1 Answer

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Answer:

The equation for this ellipse is
(x^(2))/(64) + (y^(2))/(16) = 1.

Explanation:

The standard equation of the ellipse is described by the following expression:


(x^(2))/(a^(2))+(y^(2))/(b^(2)) = 1

Where
a and
b are the horizontal and vertical semi-axes, respectively. Given that major semi-axis is horizontal,
a > b. Then, the equation for this ellipse is written in this way: (a = 8, b = 4)


(x^(2))/(64) + (y^(2))/(16) = 1

The equation for this ellipse is
(x^(2))/(64) + (y^(2))/(16) = 1.

User Prez
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