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A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it reaches a final volume of 18.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

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Answer:

the final mole of the flexible container = 12.92 moles

Step-by-step explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,


n= (V_2*n_1)/(V_1)


n= (18.3*6.51)/(6.13)

n = 19.43


n=n_1+n_2

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

User Ashish Bhatt
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