Question

A manometer connected to a Pitot-static tube has a difference in the height of the two columns of water of 10 cm when the Pitot-static tube is placed in a flow of air at standard sea level conditions. What is the velocity of the airflow

Answer 1

v = 40 m/s

Step-by-step explanation:

Difference in the height of the two columns:

`h_m = \triangle h = 10 cm \\h_m = 0.1 m`

Air density,
`\rho_(air) = 1.225 kg/m^3`

Water density,
`\rho_(w) = 1000 kg/m^3`

The velocity of air flow is given by the equation:

`v = \sqrt{2gh_m ((p_w)/(p_(air)) - 1) } \\\\v = \sqrt{2*9.81*0.1 ((1000)/(1.225) - 1) }\\\\v = 40 m/s`