Question

What is the surface area of a rectangular solid

with a length of seven inches, a width of five inches,
and a height of six inches?

Answer 1

214 inches squared

Explanation:

First, we use the equation for surface area of a rectangular prism:

SA= 2lw + 2wh +2lh

Then we can plug in given values and solve.

SA= 2(7)(5) +2(5)(6) +2(7)(6)

SA= 70 +60 +84

SA= 214 inches squared

hope this helped!

Answer 2

A = 214 in^2

Explanation:

Subdivide the "surface area" as follows: top/bottom (1 each); ends (2); sides (2).

Total top and bottom surface area is A1 = 2(length)(width), or

2(7 in)(5 in) = 70 in^2

Total area of sides is A2 = 2(length)(height) = 2(7 in)(6 in) = 84 in^2

Total area of ends is A3 = 2(width)(height) = 2(5 in)(6 in) = 60 in^2

The total surface area of this rectangular solid is A = A1*A2*A3, or

A = (84 + 60 + 70) in^2, or A = 214 in^2