How many complex and real roots are in the problem (x+10)^9.

Question

asked Sep 3, 2021 130k views

1 Answer

Uber · Answer 1 · 2021-09-08T15:29:06+0000

Answer:

9 roots

Explanation:

(x+10)^9 = 0

If you would multiply it out, the highest power is x^9 so the equation has 9 roots

Solving (x+10)^9 =0

Taking the 9th root of each sdie

x+10 = 0

x = -10

The root is -10 with multiplicity of 9