Question

An object is dropped from a height of 1024 feet off the ground. The height h of the object after t seconds can be found using the equation h = 1024 − 16 t 2

Answer 1

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An object is dropped from a height of 1024 feet off the ground. The height h of the object after t seconds can be found using the equation h = 1024 − 16t^2. how much time the object will take to reach the ground?

Answer:

`t = 8 \: seconds`

It will take 8 seconds for the object to reach the ground.

Explanation:

The given equation is

`h = 1024 - 16t^2`

Where h is the height in feet of the object after t seconds.

We are asked to find the time that the object will take to reach the ground.

What will be the height of the object when it hits the ground?

h = 0 ft

Yes right!

So, let us substitute h = 0 in the above equation to find the time.

`h = 1024 - 16t^2 \\\\0 = 1024 - 16t^2 \\\\16t^2 = 1024 \\\\t^2 = (1024)/(16) \\\\t^2 = 64 \\\\t = √(64) \\\\t = \pm 8`

Since we know that time cannot be negative

`t = 8 \: seconds`

Therefore, it will take 8 seconds for the object to reach the ground.