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Calculate the theoretical percentage of water for the following hydrates.

(a) manganese(II) monohydrate, MnSO4 H2O
(b) manganese(II) tetrahydrate, MnSO4 4H2O

User Jiddo
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1 Answer

2 votes

Answer:

(a)
\% H_2O=10.65\%

(b)
\% H_2O=32.2

Step-by-step explanation:

Hello.

For this questions we must consider the ratio of the molar mass of water to hydrated compound molar mass as shown below:

(a) In this case, we can consider that inside the manganese (II) sulfate monohydrate, whose molar mass is 169.02 g/mol, there is one water molecule that has a molar mass of 18 g/mol, for which the theoretical percentage of water is:


\% H_2O=(18g/mol)/(169.0g/mol) *100\%\\\\\% H_2O=10.65\%

(b) In this case, we can consider that inside the manganese (II) sulfate tetrahydrate, whose molar mass is 223.1 g/mol, there are four water molecules that have a molar mass of 4*18 g/mol, for which the theoretical percentage of water is:


\% H_2O=(4*18g/mol)/(223.1g/mol) *100\%\\\\\% H_2O=32.27\%

Best regards.

User David Morton
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