Answer: 0.00153
Explanation:
Given: An experiment consists of dealing 7 cards from a standard deck of 52 playing cards.
Number of ways of dealing 7 cards from 52 cards =
![^(52)C_7](https://img.qammunity.org/2021/formulas/mathematics/college/gk9rilwq6743cpbpxorizu0tq98d9qkbhs.png)
Since there are 13 clubs and 13 spades.
Number of ways of getting exactly 4 clubs and 3 spades=
![^(13)C_4*\ ^(13)C_3](https://img.qammunity.org/2021/formulas/mathematics/college/bj1ppgm74eah00yvod44th0qqal8h5dbnq.png)
Now, the probability of being dealt exactly 4 clubs and 3 spades
![=(^(13)C_4*\ ^(13)C_3)/(^(52)C_7)\\\\\\=\frac{{(13!)/(4!(9!))*(13!)/(3!10!)}}{(52!)/(7!45!)}\\\\=(715*286)/(133784560)\\\\=0.00152850224271\approx0.00153](https://img.qammunity.org/2021/formulas/mathematics/college/5szpucyzmz0m3llvgbs29yoj6d6phzqpii.png)
Hence, the probability of being dealt exactly 4 clubs and 3 spades = 0.00153