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An experiment consists of dealing 7 cards from a standard deck of 52 playing cards. What is the probability of being dealt exactly 4 clubs and 3 spades?

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Answer: 0.00153

Explanation:

Given: An experiment consists of dealing 7 cards from a standard deck of 52 playing cards.

Number of ways of dealing 7 cards from 52 cards =
^(52)C_7

Since there are 13 clubs and 13 spades.

Number of ways of getting exactly 4 clubs and 3 spades=
^(13)C_4*\ ^(13)C_3

Now, the probability of being dealt exactly 4 clubs and 3 spades


=(^(13)C_4*\ ^(13)C_3)/(^(52)C_7)\\\\\\=\frac{{(13!)/(4!(9!))*(13!)/(3!10!)}}{(52!)/(7!45!)}\\\\=(715*286)/(133784560)\\\\=0.00152850224271\approx0.00153

Hence, the probability of being dealt exactly 4 clubs and 3 spades = 0.00153

User Thilak Rao
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